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-11x^2-13x+6=0
a = -11; b = -13; c = +6;
Δ = b2-4ac
Δ = -132-4·(-11)·6
Δ = 433
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{433}}{2*-11}=\frac{13-\sqrt{433}}{-22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{433}}{2*-11}=\frac{13+\sqrt{433}}{-22} $
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